Pierre had 5 times as many green markers as red markers. After giving away 2 green markers and buying another 26 red markers, he had an equal number of green and red markers. How many green markers did Pierre have at first?
| |
Green markers |
Red markers |
| Before |
5 u |
1 u |
| Change |
- 2 |
+ 26 |
| After |
5 u - 2 |
1 u + 26 |
The number of green and red markers is the same in the end.
5 u - 2 = 1 u + 26
5 u - 1 u = 26 + 2
4 u = 2 + 26
4 u = 28
1 u = 28 ÷ 4 = 7
Number of green markers that Pierre had at first
= 5 u
= 5 x 7
= 35
Answer(s): 35
