Mrs Yeo had a sum of money. She gave her niece $1834 and gave
14 of the remaining money to her son. She used
34 of the rest of the money on a notebook and was left with
110 of the amount she had at first. What was the sum of money she had at first?
| Her niece |
Her son |
Remaining amount |
Total |
| $1834 |
1x4 |
3x4 |
|
| |
|
Notebook |
Left |
|
| |
|
3x3 |
1x3 |
|
9x3 =
27 u |
1x3 =
3 u |
|
| 14 u |
4 u |
9 u |
3 u |
30 u |
Fraction of the remaining amount left
= 1 -
34=
14The remaining amount is repeated. Make the remaining amount the same. LCM of 3 and 4 is 12.
The amount left is repeated. Make the amount left the same.
14 Remaining amount =
110 Total amount
Amount that Mrs Yeo gave to her niece
= 27 u - 4 u - 9 u
= 14 u
14 u = 1834
1 u = 1834 ÷ 14 = 131
Total amount that Mrs Yeo had at first
= 14 u + 4 u + 9 u + 3 u
= 30 u
= 30 x 131
= $3930
Answer(s): $3930
