Mrs Seow had a sum of money. She gave her niece $492 and gave
14 of the remaining money to her son. She used
45 of the rest of the money on a laptop and was left with
18 of the amount she had at first. What was the sum of money she had at first?
Her niece |
Her son |
Remaining amount |
Total |
$492 |
1x5 |
3x5 |
|
|
|
Laptop |
Left |
|
|
|
4x3 |
1x3 |
|
7x3 = 21 u |
1x3 = 3 u |
|
4 u |
5 u |
12 u |
3 u |
24 u |
Fraction of the remaining amount left
= 1 -
45=
15The remaining amount is repeated. Make the remaining amount the same. LCM of 3 and 5 is 15.
The amount left is repeated. Make the amount left the same.
15 Remaining amount =
18 Total amount
Amount that Mrs Seow gave to her niece
= 21 u - 5 u - 12 u
= 4 u
4 u = 492
1 u = 492 ÷ 4 = 123
Total amount that Mrs Seow had at first
= 4 u + 5 u + 12 u + 3 u
= 24 u
= 24 x 123
= $2952
Answer(s): $2952