Mrs Leow had a sum of money. She gave her son $312 and gave
14 of the remaining money to her father. She used
34 of the rest of the money on a television and was left with
16 of the amount she had at first. What was the sum of money she had at first?
Her son |
Her father |
Remaining amount |
Total |
$312 |
1x4 |
3x4 |
|
|
|
Television |
Left |
|
|
|
3x3 |
1x3 |
|
5x3 = 15 u |
1x3 = 3 u |
|
2 u |
4 u |
9 u |
3 u |
18 u |
Fraction of the remaining amount left
= 1 -
34=
14The remaining amount is repeated. Make the remaining amount the same. LCM of 3 and 4 is 12.
The amount left is repeated. Make the amount left the same.
14 Remaining amount =
16 Total amount
Amount that Mrs Leow gave to her son
= 15 u - 4 u - 9 u
= 2 u
2 u = 312
1 u = 312 ÷ 2 = 156
Total amount that Mrs Leow had at first
= 2 u + 4 u + 9 u + 3 u
= 18 u
= 18 x 156
= $2808
Answer(s): $2808