There was 10.4 ℓ of water in a pail and 1.6 ℓ of water in a basin. Riordan then poured in an equal volume of water into each container. Now, the volume of water in the pail is 5 times in the basin. How much water did Riordan pour into each container?
| |
Basin |
Pail |
Difference |
| Before |
10.4 ℓ |
1.6 ℓ |
8.8 ℓ |
| Change |
+ ? |
+ ? |
|
| After |
5 u |
1 u |
4 u |
Difference in the volume of water between the pail and the basin
= 10.4 - 1.6
= 8.8 ℓ
Since Riordan poured in an equal volume of water into each container, the difference in the volume of water at first and in the end remains the same.
4 u = 8.8
1 u = 8.8 ÷ 4 = 2.2
Volume of water that Riordan poured into each container
= 1 u - 1.6
= 2.2 - 1.6
= 0.6 ℓ
Answer(s): 0.6 ℓ
