Opal paid $12 for 6 wafers and 8 strudels. A strudel cost thrice as much as a wafer.
- Find the cost of a wafer in cents.
- How much more did she pay for a strudel than a wafer?
| |
Wafers |
Strudels |
Total |
| Number |
6 |
8 |
|
| Value |
1 u |
3 u |
|
| Total value |
6 u |
24 u |
30 u |
(a)
Cost of 1 wafer = 1 u
Cost of 1 strudel = 3 u
Cost of 6 wafers
= 6 x 1 u
= 6 u
Cost of 8 strudels
= 8 x 3 u
= 24 u
Total cost of 6 wafers and 8 strudels
= 6 u + 24 u
= 30 u
$1 = 100¢
$12 = 12 x 100 = 1200¢
30 u = 1200
1 u = 1200 ÷ 30 = 40
Cost of a bun
= 1 u
= 40¢
(b)
Amount that Opal paid more for a strudel than a wafer
= 6 u - 1 u
= 5 u
= 5 x 40
= 200¢
200¢ = $2
Answer(s): (a) 40¢ (b) $2
