Opal paid $3 for 6 wafers and 3 pizzas. A pizza cost thrice as much as a wafer.
- Find the cost of a wafer in cents.
- How much more did she pay for a pizza than a wafer?
|
Wafers |
Pizzas |
Total |
Number |
6 |
3 |
|
Value |
1 u |
3 u |
|
Total value |
6 u |
9 u |
15 u |
(a)
Cost of 1 wafer = 1 u
Cost of 1 pizza = 3 u
Cost of 6 wafers
= 6 x 1 u
= 6 u
Cost of 3 pizzas
= 3 x 3 u
= 9 u
Total cost of 6 wafers and 3 pizzas
= 6 u + 9 u
= 15 u
$1 = 100¢
$3 = 3 x 100 = 300¢
15 u = 300
1 u = 300 ÷ 15 = 20
Cost of a bun
= 1 u
= 20¢
(b)
Amount that Opal paid more for a pizza than a wafer
= 6 u - 1 u
= 5 u
= 5 x 20
= 100¢
100¢ = $1
Answer(s): (a) 20¢ (b) $1