Opal paid $24 for 6 biscuits and 8 pizzas. A pizza cost thrice as much as a biscuit.
- Find the cost of a biscuit in cents.
- How much more did she pay for a pizza than a biscuit?
|
Biscuits |
Pizzas |
Total |
Number |
6 |
8 |
|
Value |
1 u |
3 u |
|
Total value |
6 u |
24 u |
30 u |
(a)
Cost of 1 biscuit = 1 u
Cost of 1 pizza = 3 u
Cost of 6 biscuits
= 6 x 1 u
= 6 u
Cost of 8 pizzas
= 8 x 3 u
= 24 u
Total cost of 6 biscuits and 8 pizzas
= 6 u + 24 u
= 30 u
$1 = 100¢
$24 = 24 x 100 = 2400¢
30 u = 2400
1 u = 2400 ÷ 30 = 80
Cost of a bun
= 1 u
= 80¢
(b)
Amount that Opal paid more for a pizza than a biscuit
= 6 u - 1 u
= 5 u
= 5 x 80
= 400¢
400¢ = $4
Answer(s): (a) 80¢ (b) $4