Liam had $3.20 less than Dylan. After Liam gave $2.70 to Dylan, Dylan would have thrice as much money as Liam. How much money had Dylan at first?
| |
Dylan |
Liam |
| Before |
3 u - $2.70 |
1 u + $2.70 |
| Change |
+ $2.70 |
- $2.70 |
| After |
3 u |
1 u |
Liam had $3.20 less than Dylan. If another $3.20 was given to Liam, Dylan and Liam would have the same amount at first.
3 u - 2.70 = 1 u + 2.70 + 3.20
3 u - 1 u = 2.70 + 3.20 + 2.70
2 u = 8.60
1 u = 8.60 ÷ 2 = 4.30
Amount that Dylan had at first
= 3 u - 2.70
= 3 x 4.30 + 2.70
= 12.90 + 2.70
= $15.60
Answer(s): $15.60
