Yoko, Jade and Tammy had jelly beans in the ratio of 12 : 7 : 2. After Yoko gave 40 jelly beans to Jade and Tammy, the three of them had the same number of jelly beans. Find the total number of jelly beans the children had.
| |
Yoko |
Jade |
Tammy |
Total |
| Before |
12 u |
7 u |
2 u |
21 u |
| Change |
- 40 |
+ 40 |
|
| After |
7 u |
7 u |
7 u |
21 u |
Total number of jelly beans
= 12 u + 7 u + 2 u
= 21 u
Number of jelly beans that each had in the end
= 21 u ÷ 3
= 7 u
Number of jelly beans that Yoko gave to Jade and Tammy
= 12 u - 7 u
= 5 u
5 u = 40
1 u = 40 ÷ 5 = 8
Total number of jelly beans
= 21 u
= 21 x 8
= 168
Answer(s): 168
