Tiffany, Hazel and Gillian had sweets in the ratio of 11 : 7 : 3. After Tiffany gave 76 sweets to Hazel and Gillian, the three of them had the same number of sweets. Find the total number of sweets the children had.
| |
Tiffany |
Hazel |
Gillian |
Total |
| Before |
11 u |
7 u |
3 u |
21 u |
| Change |
- 76 |
+ 76 |
|
| After |
7 u |
7 u |
7 u |
21 u |
Total number of sweets
= 11 u + 7 u + 3 u
= 21 u
Number of sweets that each had in the end
= 21 u ÷ 3
= 7 u
Number of sweets that Tiffany gave to Hazel and Gillian
= 11 u - 7 u
= 4 u
4 u = 76
1 u = 76 ÷ 4 = 19
Total number of sweets
= 21 u
= 21 x 19
= 399
Answer(s): 399
