Nicole, Eva and Fanny had sweets in the ratio of 11 : 8 : 2. After Nicole gave 80 sweets to Eva and Fanny, the three of them had the same number of sweets. Find the total number of sweets the children had.
| |
Nicole |
Eva |
Fanny |
Total |
| Before |
11 u |
8 u |
2 u |
21 u |
| Change |
- 80 |
+ 80 |
|
| After |
7 u |
7 u |
7 u |
21 u |
Total number of sweets
= 11 u + 8 u + 2 u
= 21 u
Number of sweets that each had in the end
= 21 u ÷ 3
= 7 u
Number of sweets that Nicole gave to Eva and Fanny
= 11 u - 7 u
= 4 u
4 u = 80
1 u = 80 ÷ 4 = 20
Total number of sweets
= 21 u
= 21 x 20
= 420
Answer(s): 420
