Hilda, Vanessa and Kimberly had sweets in the ratio of 11 : 4 : 3. After Hilda gave 10 sweets to Vanessa and Kimberly, the three of them had the same number of sweets. Find the total number of sweets the children had.
| |
Hilda |
Vanessa |
Kimberly |
Total |
| Before |
11 u |
4 u |
3 u |
18 u |
| Change |
- 10 |
+ 10 |
|
| After |
6 u |
6 u |
6 u |
18 u |
Total number of sweets
= 11 u + 4 u + 3 u
= 18 u
Number of sweets that each had in the end
= 18 u ÷ 3
= 6 u
Number of sweets that Hilda gave to Vanessa and Kimberly
= 11 u - 6 u
= 5 u
5 u = 10
1 u = 10 ÷ 5 = 2
Total number of sweets
= 18 u
= 18 x 2
= 36
Answer(s): 36
