Ivory, Shannon and Betty had sweets in the ratio of 8 : 3 : 1. After Ivory gave 48 sweets to Shannon and Betty, the three of them had the same number of sweets. Find the total number of sweets the children had.
| |
Ivory |
Shannon |
Betty |
Total |
| Before |
8 u |
3 u |
1 u |
12 u |
| Change |
- 48 |
+ 48 |
|
| After |
4 u |
4 u |
4 u |
12 u |
Total number of sweets
= 8 u + 3 u + 1 u
= 12 u
Number of sweets that each had in the end
= 12 u ÷ 3
= 4 u
Number of sweets that Ivory gave to Shannon and Betty
= 8 u - 4 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Total number of sweets
= 12 u
= 12 x 12
= 144
Answer(s): 144
