Shiyun, Mary and Tiffany had candy canes in the ratio of 10 : 7 : 1. After Shiyun gave 64 candy canes to Mary and Tiffany, the three of them had the same number of candy canes. Find the total number of candy canes the children had.
| |
Shiyun |
Mary |
Tiffany |
Total |
| Before |
10 u |
7 u |
1 u |
18 u |
| Change |
- 64 |
+ 64 |
|
| After |
6 u |
6 u |
6 u |
18 u |
Total number of candy canes
= 10 u + 7 u + 1 u
= 18 u
Number of candy canes that each had in the end
= 18 u ÷ 3
= 6 u
Number of candy canes that Shiyun gave to Mary and Tiffany
= 10 u - 6 u
= 4 u
4 u = 64
1 u = 64 ÷ 4 = 16
Total number of candy canes
= 18 u
= 18 x 16
= 288
Answer(s): 288
