Natalie, Marion and Tammy had chocolate bars in the ratio of 8 : 4 : 3. After Natalie gave 9 chocolate bars to Marion and Tammy, the three of them had the same number of chocolate bars. Find the total number of chocolate bars the children had.
| |
Natalie |
Marion |
Tammy |
Total |
| Before |
8 u |
4 u |
3 u |
15 u |
| Change |
- 9 |
+ 9 |
|
| After |
5 u |
5 u |
5 u |
15 u |
Total number of chocolate bars
= 8 u + 4 u + 3 u
= 15 u
Number of chocolate bars that each had in the end
= 15 u ÷ 3
= 5 u
Number of chocolate bars that Natalie gave to Marion and Tammy
= 8 u - 5 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Total number of chocolate bars
= 15 u
= 15 x 3
= 45
Answer(s): 45
