Howard and Gabriel share a bunch of chikoos in the ratio 9 : 2. If Howard gives Gabriel 56 chikoos from his share, they will have the same number of chikoos. How many chikoos does Howard have at first?
| |
Howard |
Gabriel |
| Before |
9 u |
2 u |
| Change |
- 56 |
+ 56 |
| After |
9 u - 56 |
2 u + 56 |
If Howard gives Gabriel 56 chikoos from his share, they will have the same number of chikoos.
9 u - 56 = 2 u + 56
9 u - 2 u = 56 + 56
7 u = 112
1 u = 112 ÷ 7 = 16
Number of chikoos that Howard has
= 9 u
= 9 x 16
= 144
Answer(s): 144
