Luke and Xavier share a bunch of oranges in the ratio 9 : 4. If Luke gives Xavier 50 oranges from his share, they will have the same number of oranges. How many oranges does Luke have at first?
| |
Luke |
Xavier |
| Before |
9 u |
4 u |
| Change |
- 50 |
+ 50 |
| After |
9 u - 50 |
4 u + 50 |
If Luke gives Xavier 50 oranges from his share, they will have the same number of oranges.
9 u - 50 = 4 u + 50
9 u - 4 u = 50 + 50
5 u = 100
1 u = 100 ÷ 5 = 20
Number of oranges that Luke has
= 9 u
= 9 x 20
= 180
Answer(s): 180
