Pierre and Xavier share a bunch of chikoos in the ratio 5 : 3. If Pierre gives Xavier 14 chikoos from his share, they will have the same number of chikoos. How many chikoos does Pierre have at first?
|
Pierre |
Xavier |
Before |
5 u |
3 u |
Change |
- 14 |
+ 14 |
After |
5 u - 14 |
3 u + 14 |
If Pierre gives Xavier 14 chikoos from his share, they will have the same number of chikoos.
5 u - 14 = 3 u + 14
5 u - 3 u = 14 + 14
2 u = 28
1 u = 28 ÷ 2 = 14
Number of chikoos that Pierre has
= 5 u
= 5 x 14
= 70
Answer(s): 70