Xavier and Jeremy share a bunch of oranges in the ratio 7 : 5. If Xavier gives Jeremy 23 oranges from his share, they will have the same number of oranges. How many oranges does Xavier have at first?
|
Xavier |
Jeremy |
Before |
7 u |
5 u |
Change |
- 23 |
+ 23 |
After |
7 u - 23 |
5 u + 23 |
If Xavier gives Jeremy 23 oranges from his share, they will have the same number of oranges.
7 u - 23 = 5 u + 23
7 u - 5 u = 23 + 23
2 u = 46
1 u = 46 ÷ 2 = 23
Number of oranges that Xavier has
= 7 u
= 7 x 23
= 161
Answer(s): 161