Peter and Simon share a bunch of chikoos in the ratio 9 : 5. If Peter gives Simon 40 chikoos from his share, they will have the same number of chikoos. How many chikoos does Peter have at first?
| |
Peter |
Simon |
| Before |
9 u |
5 u |
| Change |
- 40 |
+ 40 |
| After |
9 u - 40 |
5 u + 40 |
If Peter gives Simon 40 chikoos from his share, they will have the same number of chikoos.
9 u - 40 = 5 u + 40
9 u - 5 u = 40 + 40
4 u = 80
1 u = 80 ÷ 4 = 20
Number of chikoos that Peter has
= 9 u
= 9 x 20
= 180
Answer(s): 180
