Jenson and Gabriel share a bunch of chikoos in the ratio 5 : 3. If Jenson gives Gabriel 21 chikoos from his share, they will have the same number of chikoos. How many chikoos does Jenson have at first?
| |
Jenson |
Gabriel |
| Before |
5 u |
3 u |
| Change |
- 21 |
+ 21 |
| After |
5 u - 21 |
3 u + 21 |
If Jenson gives Gabriel 21 chikoos from his share, they will have the same number of chikoos.
5 u - 21 = 3 u + 21
5 u - 3 u = 21 + 21
2 u = 42
1 u = 42 ÷ 2 = 21
Number of chikoos that Jenson has
= 5 u
= 5 x 21
= 105
Answer(s): 105
