Lee and Ken share a bunch of oranges in the ratio 10 : 3. If Lee gives Ken 70 oranges from his share, they will have the same number of oranges. How many oranges does Lee have at first?
| |
Lee |
Ken |
| Before |
10 u |
3 u |
| Change |
- 70 |
+ 70 |
| After |
10 u - 70 |
3 u + 70 |
If Lee gives Ken 70 oranges from his share, they will have the same number of oranges.
10 u - 70 = 3 u + 70
10 u - 3 u = 70 + 70
7 u = 140
1 u = 140 ÷ 7 = 20
Number of oranges that Lee has
= 10 u
= 10 x 20
= 200
Answer(s): 200
