Lee and Xavier share a bunch of oranges in the ratio 9 : 4. If Lee gives Xavier 25 oranges from his share, they will have the same number of oranges. How many oranges does Lee have at first?
| |
Lee |
Xavier |
| Before |
9 u |
4 u |
| Change |
- 25 |
+ 25 |
| After |
9 u - 25 |
4 u + 25 |
If Lee gives Xavier 25 oranges from his share, they will have the same number of oranges.
9 u - 25 = 4 u + 25
9 u - 4 u = 25 + 25
5 u = 50
1 u = 50 ÷ 5 = 10
Number of oranges that Lee has
= 9 u
= 9 x 10
= 90
Answer(s): 90
