Last Friday, Seth withdrew an equal number of $10-notes and $50-notes from the bank. After spending 39 pieces of $10-notes and 11 pieces of $50-notes, the ratio of the remaining $10-notes to $50-notes became 5 : 9.
- How many $10-notes had he left?
- What was the total value of the notes which Seth withdrew from the bank?
| |
$10-notes |
$50-notes |
| Before |
5 u + 39 |
9 u + 11 |
| Change |
- 39 |
- 11 |
| After |
5 u |
9 u |
(a)
Seth withdrew an equal number of $10-notes and $50-notes from the bank. So, the number of notes of each type is the same.
9 u + 11 = 5 u + 39
9 u - 5 u = 39 - 11
4 u = 28
1 u = 28 ÷ 4 = 7
Number of $10 notes that Seth had left
= 5 u
= 5 x 7
= 35
(b)
Number of each type of notes that Seth withdrew
= 35 + 39
= 74
Value of one set of $10-note and 50-note
= 10 + 50
= $60
Total value of the notes that Seth withdrew
= 60 x 74
= $4440
Answer(s): (a) 35; (b) $4440
