The ratio of the number of $5-notes to $50-notes in Marion's handbag was 1 : 8. Marion exchanged 14 pieces of $50-notes for $5-notes. She then had an equal number of $5-notes and $50-notes. What was the total value of $5-notes and $50-notes in Marion's handbag at first?
|
$5-notes |
$50-notes |
Before |
1 u |
8 u |
Change |
+ 140 |
- 14 |
After |
1 u + 140 |
8 u - 14 |
Value of 14 pieces of $50-notes
= 14 x 50
= $700
Number of $5-notes that Marion exchanged for
= 700 ÷ 5
= 140
After the exchange, Marion had an equal number of $5-notes and $50-notes.
8 u - 14 = 1 u + 140
8 u - 1 u = 140 + 14
7 u = 154
1 u = 154 ÷ 7 = 22
Number of $5-notes at first
= 1 u
= 22
Value of $5-notes at first
= 22 x 5
= $110
Number of $50-notes at first
= 8 u
= 8 x 22
= 176
Value of $50-notes at first
= 176 x 50
= $8800
Total value of $5-notes and $50-notes at first
= 110 + 8800
= $8910
Answer(s): $8910