Cole had $95.10 more than Xavier. After Xavier had spent
49 of his money, Cole had $150.70 more than Xavier. How much money did Cole have at first?
|
Cole |
Xavier |
More |
Before |
9 u + $95.10 |
9 u |
$95.10 |
Change |
|
- 4 u |
|
After |
9 u + $95.10 |
5 u |
4 u + $95.10 |
Cole had $150.70 more than Xavier in the end.
9 u + 95.10 - 5 u = 150.70
4 u + 95.10 = 150.70
4 u = 150.70 - 95.10
4 u = 55.60
1 u = 55.60 ÷ 4 = 13.90
Amount that Cole had at first
= 9 u + 95.10
= 9 x 13.90 + 95.10
= 125.10 + 95.10
= $220.20
Answer(s): $220.20