Two identical buckets S and T contained some water. Bucket S was ¹₂ filled and Bucket T was ¹₃ filled. The ratio of the total mass of Bucket S and the water in it to the total mass of Bucket T and the water in it was 7 : 6. The total mass of the two buckets and the water they contained was 1430 g. What is the mass of an empty bucket?
Mass of Bucket S and the water inside = 7 u
Mass of Bucket T and the water inside = 6 u

Total mass of the two buckets and the water inside them
= 7 u + 6 u
= 13 u

13 u = 1430

1 u = 1430 ÷ 13 = 110

Mass of Bucket S and the water in it more than mass of Bucket T and the water in it 
= 7 u - 6 u
= 1 u

Fraction of the water that Bucket S had more than Bucket T 
= ¹₂ - ¹₃
= ³₆ - ²₆
= ¹₆ 

¹₆ of the water capacity → 1 u
²₆ of the water capacity → 2 x 1 u = 2 u

Mass of an empty bucket
= 6 u - 2 u
= 4 u
= 4 x 110
= 440 g

Answer(s): 440 g