Two identical containers H and J contained some water. Container H was ¹₉ filled and Container J was ¹₁₀ filled. The ratio of the total mass of Container H and the water in it to the total mass of Container J and the water in it was 14 : 13. The total mass of the two containers and the water they contained was 5400 g. What is the mass of an empty container?
Mass of Container H and the water inside = 14 u
Mass of Container J and the water inside = 13 u

Total mass of the two containers and the water inside them
= 14 u + 13 u
= 27 u

27 u = 5400

1 u = 5400 ÷ 27 = 200

Mass of Container H and the water in it more than mass of Container J and the water in it 
= 14 u - 13 u
= 1 u

Fraction of the water that Container H had more than Container J 
= ¹₉ - ¹₁₀
= ¹⁰₉₀ - ⁹₉₀
= ¹₉₀ 

¹₉₀ of the water capacity → 1 u
⁹₉₀ of the water capacity → 9 x 1 u = 9 u

Mass of an empty container
= 13 u - 9 u
= 4 u
= 4 x 200
= 800 g

Answer(s): 800 g