Hazel had 35 more coins than Jade. After Jade gave away
17 of her coins, Hazel had twice as many coins as Jade. How many coins did Jade have at first?
| |
Hazel |
Jade |
Comparing Hazel and
Jade at first |
35 more |
|
| Before |
12 u |
7 u |
| Change |
|
- 1 u |
| After |
12 u |
6 u |
Comparing Hazel and
Jade in the end |
2x6 =
12 u |
1x6 =
6 u |
Number of coins that Jade had in the end is repeated. Make the number of coins that Jade had in the end the same. LCM of 1 and 6 is 6.
Number of coins that Hazel had at first = 12 u
Number of coins that Hazel had more than Jade at first
= 12 u - 7 u
= 5 u
5 u = 35
1 u = 35 ÷ 5 = 7
Number of coins that Jade had at first
= 7 u
= 7 x 7
= 49
Answer(s): 49
