Raeann had 48 more coins than Hilda. After Hilda gave away
25 of her coins, Raeann had thrice as many coins as Hilda. How many coins did Hilda have at first?
| |
Raeann |
Hilda |
Comparing Raeann and
Hilda at first |
48 more |
|
| Before |
9 u |
5 u |
| Change |
|
- 2 u |
| After |
9 u |
3 u |
Comparing Raeann and
Hilda in the end |
3x3 =
9 u |
1x3 =
3 u |
Number of coins that Hilda had in the end is repeated. Make the number of coins that Hilda had in the end the same. LCM of 1 and 3 is 3.
Number of coins that Raeann had at first = 9 u
Number of coins that Raeann had more than Hilda at first
= 9 u - 5 u
= 4 u
4 u = 48
1 u = 48 ÷ 4 = 12
Number of coins that Hilda had at first
= 5 u
= 5 x 12
= 60
Answer(s): 60
