Emily had 77 more coins than Linda. After Linda gave away
13 of her coins, Emily had five times as many coins as Linda. How many coins did Linda have at first?
| |
Emily |
Linda |
Comparing Emily and
Linda at first |
77 more |
|
| Before |
10 u |
3 u |
| Change |
|
- 1 u |
| After |
10 u |
2 u |
Comparing Emily and
Linda in the end |
5x2 =
10 u |
1x2 =
2 u |
Number of coins that Linda had in the end is repeated. Make the number of coins that Linda had in the end the same. LCM of 1 and 2 is 2.
Number of coins that Emily had at first = 10 u
Number of coins that Emily had more than Linda at first
= 10 u - 3 u
= 7 u
7 u = 77
1 u = 77 ÷ 7 = 11
Number of coins that Linda had at first
= 3 u
= 3 x 11
= 33
Answer(s): 33
