Julie had 33 more stickers than Xylia. After Xylia gave away
15 of her stickers, Julie had twice as many stickers as Xylia. How many stickers did Xylia have at first?
| |
Julie |
Xylia |
Comparing Julie and
Xylia at first |
33 more |
|
| Before |
8 u |
5 u |
| Change |
|
- 1 u |
| After |
8 u |
4 u |
Comparing Julie and
Xylia in the end |
2x4 =
8 u |
1x4 =
4 u |
Number of stickers that Xylia had in the end is repeated. Make the number of stickers that Xylia had in the end the same. LCM of 1 and 4 is 4.
Number of stickers that Julie had at first = 8 u
Number of stickers that Julie had more than Xylia at first
= 8 u - 5 u
= 3 u
3 u = 33
1 u = 33 ÷ 3 = 11
Number of stickers that Xylia had at first
= 5 u
= 5 x 11
= 55
Answer(s): 55
