Shiyun had 16 more coins than Shannon. After Shannon gave away
27 of her coins, Shiyun had thrice as many coins as Shannon. How many coins did Shannon have at first?
| |
Shiyun |
Shannon |
Comparing Shiyun and
Shannon at first |
16 more |
|
| Before |
15 u |
7 u |
| Change |
|
- 2 u |
| After |
15 u |
5 u |
Comparing Shiyun and
Shannon in the end |
3x5 =
15 u |
1x5 =
5 u |
Number of coins that Shannon had in the end is repeated. Make the number of coins that Shannon had in the end the same. LCM of 1 and 5 is 5.
Number of coins that Shiyun had at first = 15 u
Number of coins that Shiyun had more than Shannon at first
= 15 u - 7 u
= 8 u
8 u = 16
1 u = 16 ÷ 8 = 2
Number of coins that Shannon had at first
= 7 u
= 7 x 2
= 14
Answer(s): 14
