Nora had 63 more coins than Xuan. After Xuan gave away
37 of her coins, Nora had four times as many coins as Xuan. How many coins did Xuan have at first?
| |
Nora |
Xuan |
Comparing Nora and
Xuan at first |
63 more |
|
| Before |
16 u |
7 u |
| Change |
|
- 3 u |
| After |
16 u |
4 u |
Comparing Nora and
Xuan in the end |
4x4 =
16 u |
1x4 =
4 u |
Number of coins that Xuan had in the end is repeated. Make the number of coins that Xuan had in the end the same. LCM of 1 and 4 is 4.
Number of coins that Nora had at first = 16 u
Number of coins that Nora had more than Xuan at first
= 16 u - 7 u
= 9 u
9 u = 63
1 u = 63 ÷ 9 = 7
Number of coins that Xuan had at first
= 7 u
= 7 x 7
= 49
Answer(s): 49
