Elijah and Seth had a total of 30 coins. Seth had half as many coins as Elijah. How many coins must Elijah give to Seth so they have an equal number of coins?
| |
Elijah |
Seth |
Total |
| Before |
2 u |
1 u |
30 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 30 ÷ 3 = 10
Elijah and Seth have an equal number of coins in the end.
Number of coins that Seth has in the end
= 30 ÷ 2
= 15
Number of coins that Elijah must give to Seth
= 15 - 10
= 5
Answer(s): 5
