Xavier and Ivan had a total of 120 beads. Ivan had half as many beads as Xavier. How many beads must Xavier give to Ivan so they have an equal number of beads?
| |
Xavier |
Ivan |
Total |
| Before |
2 u |
1 u |
120 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of beads at first = 3 u
1 u = 120 ÷ 3 = 40
Xavier and Ivan have an equal number of beads in the end.
Number of beads that Ivan has in the end
= 120 ÷ 2
= 60
Number of beads that Xavier must give to Ivan
= 60 - 40
= 20
Answer(s): 20
