Oliver and Fred had a total of 108 pens. Fred had half as many pens as Oliver. How many pens must Oliver give to Fred so they have an equal number of pens?
|
Oliver |
Fred |
Total |
Before |
2 u |
1 u |
108 |
Change |
- ? |
+ ? |
|
After |
1 |
1 |
|
Total number of pens at first = 3 u
1 u = 108 ÷ 3 = 36
Oliver and Fred have an equal number of pens in the end.
Number of pens that Fred has in the end
= 108 ÷ 2
= 54
Number of pens that Oliver must give to Fred
= 54 - 36
= 18
Answer(s): 18