Gabriel and Ryan had a total of 48 coins. Ryan had half as many coins as Gabriel. How many coins must Gabriel give to Ryan so they have an equal number of coins?
| |
Gabriel |
Ryan |
Total |
| Before |
2 u |
1 u |
48 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 48 ÷ 3 = 16
Gabriel and Ryan have an equal number of coins in the end.
Number of coins that Ryan has in the end
= 48 ÷ 2
= 24
Number of coins that Gabriel must give to Ryan
= 24 - 16
= 8
Answer(s): 8
