Valen and Howard had a total of 66 coins. Howard had half as many coins as Valen. How many coins must Valen give to Howard so they have an equal number of coins?
| |
Valen |
Howard |
Total |
| Before |
2 u |
1 u |
66 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 66 ÷ 3 = 22
Valen and Howard have an equal number of coins in the end.
Number of coins that Howard has in the end
= 66 ÷ 2
= 33
Number of coins that Valen must give to Howard
= 33 - 22
= 11
Answer(s): 11
