Ethan and Simon had a total of 138 coins. Simon had half as many coins as Ethan. How many coins must Ethan give to Simon so they have an equal number of coins?
| |
Ethan |
Simon |
Total |
| Before |
2 u |
1 u |
138 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 138 ÷ 3 = 46
Ethan and Simon have an equal number of coins in the end.
Number of coins that Simon has in the end
= 138 ÷ 2
= 69
Number of coins that Ethan must give to Simon
= 69 - 46
= 23
Answer(s): 23
