Tom and Xavier had a total of 108 pens. Xavier had half as many pens as Tom. How many pens must Tom give to Xavier so they have an equal number of pens?
| |
Tom |
Xavier |
Total |
| Before |
2 u |
1 u |
108 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of pens at first = 3 u
1 u = 108 ÷ 3 = 36
Tom and Xavier have an equal number of pens in the end.
Number of pens that Xavier has in the end
= 108 ÷ 2
= 54
Number of pens that Tom must give to Xavier
= 54 - 36
= 18
Answer(s): 18
