Xavier and Carl had a total of 48 cards. Carl had half as many cards as Xavier. How many cards must Xavier give to Carl so they have an equal number of cards?
| |
Xavier |
Carl |
Total |
| Before |
2 u |
1 u |
48 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of cards at first = 3 u
1 u = 48 ÷ 3 = 16
Xavier and Carl have an equal number of cards in the end.
Number of cards that Carl has in the end
= 48 ÷ 2
= 24
Number of cards that Xavier must give to Carl
= 24 - 16
= 8
Answer(s): 8
