Bryan and David had a total of 66 coins. David had half as many coins as Bryan. How many coins must Bryan give to David so they have an equal number of coins?
|
Bryan |
David |
Total |
Before |
2 u |
1 u |
66 |
Change |
- ? |
+ ? |
|
After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 66 ÷ 3 = 22
Bryan and David have an equal number of coins in the end.
Number of coins that David has in the end
= 66 ÷ 2
= 33
Number of coins that Bryan must give to David
= 33 - 22
= 11
Answer(s): 11