Riordan and Simon had a total of 72 coins. Simon had half as many coins as Riordan. How many coins must Riordan give to Simon so they have an equal number of coins?
|
Riordan |
Simon |
Total |
Before |
2 u |
1 u |
72 |
Change |
- ? |
+ ? |
|
After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 72 ÷ 3 = 24
Riordan and Simon have an equal number of coins in the end.
Number of coins that Simon has in the end
= 72 ÷ 2
= 36
Number of coins that Riordan must give to Simon
= 36 - 24
= 12
Answer(s): 12