Ahmad and Ken had a total of 60 stickers. Ken had half as many stickers as Ahmad. How many stickers must Ahmad give to Ken so they have an equal number of stickers?
| |
Ahmad |
Ken |
Total |
| Before |
2 u |
1 u |
60 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of stickers at first = 3 u
1 u = 60 ÷ 3 = 20
Ahmad and Ken have an equal number of stickers in the end.
Number of stickers that Ken has in the end
= 60 ÷ 2
= 30
Number of stickers that Ahmad must give to Ken
= 30 - 20
= 10
Answer(s): 10
