Luke and Peter had a total of 150 marbles. Peter had half as many marbles as Luke. How many marbles must Luke give to Peter so they have an equal number of marbles?
| |
Luke |
Peter |
Total |
| Before |
2 u |
1 u |
150 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of marbles at first = 3 u
1 u = 150 ÷ 3 = 50
Luke and Peter have an equal number of marbles in the end.
Number of marbles that Peter has in the end
= 150 ÷ 2
= 75
Number of marbles that Luke must give to Peter
= 75 - 50
= 25
Answer(s): 25
