Daniel and Michael had a total of 126 marbles. Michael had half as many marbles as Daniel. How many marbles must Daniel give to Michael so they have an equal number of marbles?
| |
Daniel |
Michael |
Total |
| Before |
2 u |
1 u |
126 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of marbles at first = 3 u
1 u = 126 ÷ 3 = 42
Daniel and Michael have an equal number of marbles in the end.
Number of marbles that Michael has in the end
= 126 ÷ 2
= 63
Number of marbles that Daniel must give to Michael
= 63 - 42
= 21
Answer(s): 21
