Tim and Lee had a total of 78 beads. Lee had half as many beads as Tim. How many beads must Tim give to Lee so they have an equal number of beads?
| |
Tim |
Lee |
Total |
| Before |
2 u |
1 u |
78 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of beads at first = 3 u
1 u = 78 ÷ 3 = 26
Tim and Lee have an equal number of beads in the end.
Number of beads that Lee has in the end
= 78 ÷ 2
= 39
Number of beads that Tim must give to Lee
= 39 - 26
= 13
Answer(s): 13
