George and Paul had a total of 96 coins. Paul had half as many coins as George. How many coins must George give to Paul so they have an equal number of coins?
| |
George |
Paul |
Total |
| Before |
2 u |
1 u |
96 |
| Change |
- ? |
+ ? |
|
| After |
1 |
1 |
|
Total number of coins at first = 3 u
1 u = 96 ÷ 3 = 32
George and Paul have an equal number of coins in the end.
Number of coins that Paul has in the end
= 96 ÷ 2
= 48
Number of coins that George must give to Paul
= 48 - 32
= 16
Answer(s): 16
